This is a question of conditional probabilities. Whenever you deal with conditional probabilities its a good idea to define events.
A_i = { car is behind door i }
B_i = { car is not behind door i }
basically what youre asking is what is greater:
P{ A_1 | B_3 } probability( car is behind door 1 given it is not behind door 3 )
P{ A_2 | B_3 } probability( car is behind door 2 given it is not behind door 3 )
both of these equal 1/2
Inevitably someone will say when you pick door 1, you had a 1/3 chance of succeeding, but if you switch, you will have a 1/2 chance of succeeding. That changes when new information arrives though.
I take upper level statistics, and that is the right answer.
If you know the car is not behind door 3, you know it is behind either door 1 or 2, those are the only two options, so each has a probability of 1/2 in succeeding.
For those who don't believe you can wikipedia it. The probability if you switch is 2/3. That was one of the first questions given to me by my Greek History Professor...proving to us that we shouldnt jump to conclusions.